What is the standard form equation of the line shown below?Graph of a line going through negative 3, negative 1 and 3, 2(a) y + 1 = one half(x + 3)(b) y = one halfx + five halves(c) −x + 2y = 1(d) x − 2y = −1

Answer:DStep-by-step explanation:The equation of a line in standard form isAx + By = C ( A is a positive integer and B, C are integers )Obtain the equation in point- slope formy - b = m(x - a)where m is the slope and (a, b) a point on the lineCalculate m using the slope formulam = (y₂ - y₁ ) / (x₂ - x₁ )with (x₁, y₁ ) = (- 3, - 1) and (x₂, y₂ ) = (3, 2)m = [tex]\frac{2+1}{3+3}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]Use either of the 2 points as the point on the lineUsing (- 3, - 1), theny - (- 1) = [tex]\frac{1}{2}[/tex](x - (- 3)), that isy + 1 = [tex]\frac{1}{2}[/tex](x + 3) ← in point- slope formMultiply all terms on both sides by 22y + 2 = x + 3 ( subtract 2y from both sides )2 = x - 2y + 3 ( subtract 3 from both sides )- 1 = x - 2y , that isx - 2y = - 1 ← in standard form → D