If the sum of three consecutive numbers is 36. Find the numbers.
Accepted Solution
A:
Answer:11, 12, 13Step-by-step explanation:
x is the first number
(x + 1) is the second number
(x + 2) is the third numberx + x+1 + x+2 = 363x + 3 = 363x = 36 - 33x = 33x = 11 Β β the first number
the second number Β = x + 1 = 11 + 1 = 12the third number = x + 2 = 11 + 2 = 13